1074=16t^2

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Solution for 1074=16t^2 equation:



1074=16t^2
We move all terms to the left:
1074-(16t^2)=0
a = -16; b = 0; c = +1074;
Δ = b2-4ac
Δ = 02-4·(-16)·1074
Δ = 68736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{68736}=\sqrt{64*1074}=\sqrt{64}*\sqrt{1074}=8\sqrt{1074}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{1074}}{2*-16}=\frac{0-8\sqrt{1074}}{-32} =-\frac{8\sqrt{1074}}{-32} =-\frac{\sqrt{1074}}{-4} $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{1074}}{2*-16}=\frac{0+8\sqrt{1074}}{-32} =\frac{8\sqrt{1074}}{-32} =\frac{\sqrt{1074}}{-4} $

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